Lab_1_Solutions

Lab_1_Solutions - 1 O O O O O O O O O O O O O O MATH 137...

Info iconThis preview shows pages 1–4. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 1 O O O O O O O O O O O O O O MATH 137 Maple Lab 1 - Assignment Solutions Mathematical Functions and Bisection Problem 1: Solving Equations 1a) restart : plot 3 $ cos 3 $ x , x 2 , x = K 4 ..4, colour = "Red", "Blue" ; K 4 K 3 K 2 K 1 1 2 3 4 K 3 K 2 K 1 1 2 3 1b) fsolve 3 $ cos 3 $ x = x 2 , x , K 4 .. K 3 ; K 3.460290751 fsolve 3 $ cos 3 $ x = x 2 , x , K 3 .. K 2 ; K 2.778483111 fsolve 3 $ cos 3 $ x = x 2 , x , K 2 .. K 1 ; K 1.487298170 fsolve 3 $ cos 3 $ x = x 2 , x , K 1 ..0 ; K 0.5544452995 fsolve 3 $ cos 3 $ x = x 2 , x , 0 ..1 ; 0.4960111186 2 O O O O O O O O O O O O fsolve 3 $ cos 3 $ x = x 2 , x , 1 ..2 ; 1.664497583 fsolve 3 $ cos 3 $ x = x 2 , x , 2 ..3 ; 2.476189113 fsolve 3 $ cos 3 $ x = x 2 , x , 3 ..4 ; 3.901135962 ANSWER : ANSWER : Thus, the solutions in the interval K 4, 4 are K 3.460290751, K 2.778483111, K 1.487298170, K 0.5544452995, 0.4960111186, 1.664497583, 2.476189113, 3.901135962. Problem 2: The Heaviside Function 2a) restart : f d x / K x K 1 K Heaviside x C 1 $ K x K 1 C Heaviside x C 1 $ x K Heaviside x K 1 $ x C Heaviside x K 1 $ x K 1 2 ; f := x / K x K 1 K Heaviside x C 1 K x K 1 C Heaviside x C 1 x K Heaviside x K 1 x C Heaviside x K 1 x K 1 2 2b) plot f x , x = K 3 ..3, discont = true ; K 3 K 2 K 1 1 2 3 K 1 1 2 3 4 3 O O O O O O O O Problem 3: Domains and Discontinuities 3a) restart : plot 3.9 $ x K 2 K x 2 , x = K 1 ..4 ; x K 1 1 2 3 4 K 6 K 5 K 4 K 3 K 2 K 1 1 solve 3.9 $ x K 2 K x 2 ; 0.6074278418, 3.292572158 fsolve tan 2 $ x K x , x , 0.6074278418 ..3.292572158 ; 2.137391136 ANSWER : Since $ is defined only where $ R 0 , the domain of f x is wherever tan 2 x K x s 0 , and tan 2 x is defined, within the interval 0.6074278418, 3.2925721580....
View Full Document

This note was uploaded on 02/21/2010 for the course MATH 137 taught by Professor Speziale during the Spring '08 term at Waterloo.

Page1 / 10

Lab_1_Solutions - 1 O O O O O O O O O O O O O O MATH 137...

This preview shows document pages 1 - 4. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online