G&Sed4ansChap2(HW!)

G&Sed4ansChap2(HW!) - b) motor pf = 0.873 lagging...

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th Edition Chapter 2 Answers 2.1 a) A 1 =2.5+j4.33 b) A 2 =5/-126.9 o c) A 3 =-.5+j.33 d) A 4 =9.821-j22.99 e) A 5 =1/-66.9 2.3 a) V m =678.8 Vb) V rms =480 V c) V =480/-105 V I=141.5/-5 A 2.10 a) p= -11787 +67780 Cos(2ωt-110) W b) P=-11,790 W delivered c) Q=-66850 Var delivered d) pf= 0.174 lagging 2.12 a) P R =23,038(1-sin(2ωt)) W b) P c = -9215 Cos(2ωt) W c) P= 23040 W d) Q= -9215 Var e) pf = .928 leading 2.19 a) S= 375 +j650 VA b) pf = 0.5 lagging c) Q=181.6 Var Q c =468 Var 2.20 S 1 =433+j250 VA S 2 =500 – j500 VA S 1 + S 2 =933-j250 VA 2.21 a) Q c = 535.9 kVA
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Unformatted text preview: b) motor pf = 0.873 lagging 2.22 a) P 1 =937.3 W P 2 =1062.7 W b) I = 19.417 j15.16 A 2.23 P=2.6 KW delivered Q = 1.5 kVar absorbing 2.35 + +-+-+ = 20 10 2 1 1 . 3 88 . 5 5 . 5 5 . 1 . 3 88 . V V j j j j I I 2.40 a) Z LY = j12 b) Z L = 3 Z LY 2.41 S =5.76 +j4.32 kVA 2.45 I s = 30 /-0.5 I n = 0 2.47 a) V L =375.6 V b) V 2 =449.9 V c) S g2 = 26,619 /40.88 VA Rgf 2/5/10...
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