ch31the24squarechart

ch31the24squarechart - Example 2 : A more difficult problem...

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Chapter 31: The 24-square Chart Quite a number of probability problems revolve  around two events, A and B. Their solutions may or may not be straightforward.   Here is a mechanical way. Example 1 : Events A and B are such that P(A)=1/3,  P(B)=0.25 and P(B'|A')=0.8.  Find the probabilities P(B'|A) , P(A|B) and  P(A'UB').
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This is the 24-square chart!
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More relationships in the 24-square chart
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Solution for Example 1
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Unformatted text preview: Example 2 : A more difficult problem Given P(A|B)=1/3, P(A'UB)=0.7 and P(B'|A')=0.75. Find P(A Ⴖ B), P(AUB'), P(A'|B') and P(A' Ⴖ B') using the 24-square chart. Solution : In the left chart, the given probabilities are ticked. We let one core internal square be x . Then the other two core internal squares are 2 x and 6 x . Thus, 9 x + 0.3=1 Therefore, x =7/90...
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This note was uploaded on 02/22/2010 for the course FBE STAT0302 taught by Professor Unknown during the Spring '10 term at HKU.

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ch31the24squarechart - Example 2 : A more difficult problem...

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