HW2-solution - When C c < C h : C * = C min / C...

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ME 426 Solution to homework #2 Show that the heat exchanger effectiveness, , for a parallel flow can be expressed in terms of NTU and the capacity rate ratio as follows:     * * 1 1 exp 1 C C NTU Solution For parallel flow, h c c h c h C C UA T T T T 1 1 exp 1 1 2 2 Eq (1) When C c > C h : C * = C min / C max = C h / C c 1 1 2 1 1 1 min 2 1 ) ( ) ( c h h h c h h h h T T T T T T C T T C Eq (2) Also, ) ( ) ( ) ( 2 1 * 1 2 2 1 1 2 h h c c h h h c c c T T C T T T T C T T C Eq (3) From Eqs (2) and (3), solve for T h2 and T c2 and insert them into Eq (1). Then     * * 1 1 exp 1 C C NTU
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Unformatted text preview: When C c < C h : C * = C min / C max = C c / C h 1 1 1 2 1 1 min 1 2 ) ( ) ( c h c c c h c c c T T T T T T C T T C Eq (4) Also, 2 1 1 2 * 2 1 1 2 ) ( ) ( ) ( h h c c h h h c c c T T T T C T T C T T C Eq (5) From Eqs (4) and (5), solve for T h2 and T c2 and insert them into Eq (1). Then * * 1 1 exp 1 C C NTU...
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This note was uploaded on 02/22/2010 for the course MECHANICAL ME 426 taught by Professor Hojinahn during the Fall '09 term at Yeditepe Üniversitesi.

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