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Unformatted text preview: budynas_SM_ch03.qxd 11/28/2006 21:22 Page 42 FIRST PAGES 42 Solutions Manual • Instructor’s Solution Manual to Accompany Mechanical Engineering Design 3-27 (a) Model (c) 500 lbf 500 lbf 0.4375 1.25 in 500 lbf V (lbf) 500 500 lbf π (0.54 ) = 3.068(10−3 ) in4 64 π A = (0.52 ) = 0.1963 in2 4 Mc 218.75(0.25) σ= = I 3.068(10−3 ) = 17 825 psi = 17.8 kpsi Ans. I= τmax = 4V 4 500 = = 3400 psi 3A 3 0.1963 Ans. O 500 M (lbf • in) O Mmax 500(0.4375) 218.75 lbf • in (b) Model (d) 1333 lbf/in 0.25" 1.25" 500 lbf V (lbf) 500 50...
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