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Unformatted text preview: Y 25 = 0 . 03748 , Y 15 = 0 . 07965 , Y 25 =. 07965 C. Problem 5. Predictorcorrector using AB4AM4 for the linear system(IVP) Y 1 = y, Y 2 = y Converting the 2nd order diferential equation into a linear system, Y 1 = f 1 ( x, Y 1 , Y 2 ) = Y 2 , Y 1 (0) = 1 8 Y 2 = f 2 ( x, Y 1 , Y 2 ) =sin ( Y 1 ) , Y 2 (0) = 0 h = 10 x 2 = 10 Y 12 = Y 11 + h ( f 1 ( x, Y 11 , Y 21 ) = Y 11 + hY 21 = 0 . 39270 Y 22 = Y 21 + h ( f 2 ( x, Y 11 , Y 21 ) = Y 21 + h (sin ( Y 11 )) =. 12022 x 3 = 5 Y 13 = Y 12 + h ( f 1 ( x, Y 12 , Y 22 ) = Y 12 + hY 22 = 0 . 35493 Y 23 = Y 22 + h ( f 2 ( x, Y 12 , Y 22 ) = Y 22 + h (sin ( Y 12 )) =. 24045 2...
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This note was uploaded on 02/22/2010 for the course CHE 348 taught by Professor Chelikowsky during the Spring '08 term at University of Texas at Austin.
 Spring '08
 Chelikowsky

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