hw07_p05_answer - 0.85378 180 11.18750 0.85654 200 12.43750...

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Sheet1 Page 1 Problem 5. Tumor growth Using while loop, the number of iterations, 'n', increases to the point where the error satisfies a tolerance. h = 0.06250 ntR(t) 2 0.06250 0.26983 20 1.18750 0.52467 40 2.43750 0.67423 60 3.68750 0.75522 80 4.93750 0.80040 100 6.18750 0.82599 120 7.43750 0.84059 140 8.68750 0.84897 160 9.93750
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Unformatted text preview: 0.85378 180 11.18750 0.85654 200 12.43750 0.85814 220 13.68750 0.85906 240 14.93750 0.85959 260 16.18750 0.85989 280 17.43750 0.86007 300 18.68750 0.86017 320 19.93750 0.86023 340 21.18750 0.86026 360 22.43750 0.86028 380 23.68750 0.86029 400 24.93750 0.86030 420 26.18750 0.86030 433 27.00000 0.86031...
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This note was uploaded on 02/22/2010 for the course CHE 348 taught by Professor Chelikowsky during the Spring '08 term at University of Texas.

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