exercise 6 - Vivian Mai-Tran 10/17/2006 Exercise 6 1. mg...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Vivian Mai-Tran 10/17/2006 Exercise 6 1. mg Chl/mL = (.496)(0.020)+(.915)(0.0080) = .01724 mg Chl/mL 2. c1 x v1 = c1 x c2 (.01724 mg/mL)(10mL)=(c2)(50mL+20/(1.13)) 1.13=density of spinach c2=.0025465621 mg/mL 3. a)mg Chl a/mL = (.915)(.013)-(.496)(.0027) = .0105558 mg Chl a/mL b)mg Chl b/mL = (.496)(.023) – (.915)(.0047) = .0071075 mg Chl b/mL 4. mg Chl b/mL = .01724-.0105558 = .0066842 mg Chl b/mL There is a difference of .0004233 mg Chl b/mL(.0071075-.0066842), with the alternative formula with the higher value and the empirical formula with the lower value. 5. mg Chl a/mg Chl b = .0105558/.0071075 = 1.48516356 6. height of solvent = 126 mm PIGMENT HEIGHT (mm) Rf (height of pigment/height of solvent) Beta-Carotene 115 .9126984127 Chlorophyll A 100 .7936507937 Chlorophyll B 86 .6825396825 The most soluble pigment moves the fastest in the motile phase of the “Chromatography Developing Solution”, which would be the Beta-Carotene between the three pigments because it traveled the furthest. Since Chlorophyll B moved the least furthest, we can assume that Chlorophyll B had a great
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 02/22/2010 for the course BIO 50100 taught by Professor Brand during the Fall '09 term at University of Texas at Austin.

Page1 / 2

exercise 6 - Vivian Mai-Tran 10/17/2006 Exercise 6 1. mg...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online