exercise 6

# exercise 6 - Vivian Mai-Tran Exercise 6 1 mg Chl/mL...

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Vivian Mai-Tran 10/17/2006 Exercise 6 1. mg Chl/mL = (.496)(0.020)+(.915)(0.0080) = .01724 mg Chl/mL 2. c1 x v1 = c1 x c2 (.01724 mg/mL)(10mL)=(c2)(50mL+20/(1.13)) 1.13=density of spinach c2=.0025465621 mg/mL 3. a)mg Chl a/mL = (.915)(.013)-(.496)(.0027) = .0105558 mg Chl a/mL b)mg Chl b/mL = (.496)(.023) – (.915)(.0047) = .0071075 mg Chl b/mL 4. mg Chl b/mL = .01724-.0105558 = .0066842 mg Chl b/mL There is a difference of .0004233 mg Chl b/mL(.0071075-.0066842), with the alternative formula with the higher value and the empirical formula with the lower value. 5. mg Chl a/mg Chl b = .0105558/.0071075 = 1.48516356 6. height of solvent = 126 mm PIGMENT HEIGHT (mm) Rf (height of pigment/height of solvent) Beta-Carotene 115 .9126984127 Chlorophyll A 100 .7936507937 Chlorophyll B 86 .6825396825 The most soluble pigment moves the fastest in the motile phase of the “Chromatography Developing Solution”, which would be the Beta-Carotene between the three pigments because it traveled the furthest. Since Chlorophyll B moved the least furthest, we can assume that Chlorophyll B had a great

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exercise 6 - Vivian Mai-Tran Exercise 6 1 mg Chl/mL...

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