{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

exp0 - Anusha Vadlamudi Partner Christen Burns TA Lindsay...

Info icon This preview shows pages 1–7. Sign up to view the full content.

View Full Document Right Arrow Icon
Anusha Vadlamudi Partner: Christen Burns TA: Lindsay Aldridge Chem 241 Lab; Section 401; Room 300 Experiment 0: Statistics, Data Analysis, and Basic Lab Skills (5/13/08)
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Honor Code Pledge: I pledge that no unauthorized assistance has been given or received in the completion of the work presented in this report. Results: Exercise 1- Statistical Analysis of Filter paper: Paper # Weight (g) 8 0.641 2 0.644 16 0.641 9 0.655 4 0.645 1 0.639 13 0.650 18 0.643 14 0.650 11 0.642 Table 1: Paper #s and their corresponding weights collected during lab Sample Calculation of standard deviation using paper # 8: Standard deviation formula = 1 ) ( 1 2 - - = n x x n i i Mean, X = 10 weights = 10 450 . 6 = 0.645 Difference, ) ( X X i - = (0.641-0.645) = -0.004 Difference squared, 2 ) ( X X i - = (-0.004) 2 = 1.600E-5 Standard deviation, 1 10 ) ( 10 1 2 - - = i i x x , where n = 10, = 5.077E-3 Standard deviation was found in a similar fashion for the population data. The calculations were done in Microsoft Excel and presented below.
Image of page 2
Experiment 0: Statistical treatment of Data Student Name: Anusha Vadlamudi Chemistry 241L Date: 5/13/2008 Section: 401 TA Name: Lindsay Aldridge Population My Paper Data Difference Paper Data Difference Mass (g) (di) (di)^2 Mass (g) (di) (di)^2 0.641 -0.004 1.600E-05 0.643 -0.017 2.843E-04 0.644 -0.001 1.000E-06 0.647 -0.013 1.654E-04 0.641 -0.004 1.600E-05 0.644 -0.016 2.579E-04 0.655 0.010 1.000E-04 0.657 -0.003 8.179E-06 0.645 0.000 1.233E-32 0.649 -0.011 1.201E-04 0.639 -0.006 3.600E-05 0.644 -0.016 2.644E-04 0.650 0.005 2.500E-05 0.645 -0.015 2.329E-04 0.643 -0.002 4.000E-06 0.640 -0.020 4.064E-04 0.650 0.005 2.500E-05 0.648 -0.012 1.383E-04 0.642 -0.003 9.000E-06 0.658 -0.002 3.097E-06 SUMS= 6.450 2.320E-04 0.652 -0.008 6.178E-05 MEAN= 0.645 0.654 -0.007 4.303E-05 0.639 -0.022 4.691E-04 Standard Deviation = 5.077E-03 0.643 -0.017 2.910E-04 0.657 -0.003 1.129E-05 0.651 -0.009 8.390E-05 0.648 -0.012 1.383E-04 0.644 -0.016 2.611E-04 0.651 -0.010 9.331E-05 0.639 -0.021 4.435E-04 0.672 0.011 1.309E-04 0.677 0.017 2.769E-04 0.668 0.008 6.305E-05 0.657 -0.003 1.129E-05 0.683 0.023 5.126E-04 0.669 0.008 6.956E-05 0.682 0.022 4.858E-04 0.664 0.004 1.475E-05 0.679 0.018 3.400E-04 0.657 -0.004 1.267E-05 0.679 0.019 3.702E-04 0.664 0.004 1.475E-05 0.663 0.003 9.243E-06 0.672 0.012 1.378E-04 0.669 0.009 8.538E-05 0.663 0.003 9.861E-06 0.668 0.008 6.147E-05
Image of page 3

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
0.664 0.004 1.798E-05 0.675 0.014 2.056E-04 0.659 -0.001 1.587E-06 0.663 0.003 9.243E-06 0.662 0.002 3.764E-06 0.665 0.005 2.441E-05 0.673 0.013 1.753E-04 0.667 0.007 5.098E-05 0.672 0.012 1.426E-04 0.666 0.006 3.295E-05 0.668 0.008 5.991E-05 0.673 0.013 1.623E-04 0.688 0.027 7.530E-04 0.666 0.006 3.411E-05 0.666 0.006 3.069E-05 0.672 0.012 1.426E-04 0.684 0.023 5.448E-04 0.671 0.010 1.069E-04 0.669 0.009 7.293E-05 0.677 0.017 2.736E-04 0.663 0.003 6.971E-06 0.677 0.016 2.670E-04 0.667 0.007 5.242E-05 0.658 -0.002 3.459E-06 0.665 0.005 2.343E-05 0.670 0.010 9.881E-05 0.650 -0.010 1.012E-04 0.654 -0.006 3.672E-05 0.667 0.007 5.098E-05 0.644 -0.016 2.484E-04 0.672 0.012 1.355E-04 0.648 -0.012 1.454E-04 0.652 -0.008 7.157E-05 0.655 -0.006 3.091E-05 0.664 0.004 1.714E-05 0.651 -0.009 8.574E-05 0.668 0.008 6.464E-05 0.659 -0.001 5.773E-07 0.653 -0.007 5.126E-05 0.654 -0.006 3.434E-05 0.649 -0.011 1.245E-04 0.652 -0.008 6.496E-05 0.441 -0.219 4.812E-02 0.664 0.004 1.632E-05 0.672 0.012 1.498E-04 0.672 0.012 1.474E-04 0.678 0.017 3.042E-04 0.673 0.013 1.573E-04 0.666 0.006 3.770E-05 0.674 0.014 1.861E-04
Image of page 4
0.665 0.005 2.746E-05 0.681 0.021 4.469E-04 0.672 0.012 1.426E-04 0.659 -0.001 1.123E-06 0.657 -0.003 7.617E-06 0.668 0.008 5.685E-05 0.675 0.015 2.323E-04 0.657 -0.003 8.179E-06 0.672 0.012 1.426E-04 0.669 0.009 7.293E-05 0.670 0.010 1.049E-04 0.653 -0.007 4.844E-05 0.655 -0.005 2.560E-05 0.656 -0.004 1.901E-05 0.650 -0.010 1.073E-04 0.652 -0.009 7.499E-05 0.669 0.009 7.815E-05 0.653 -0.007 4.570E-05 0.666 0.006 3.411E-05 0.670 0.009 8.724E-05 0.668 0.008 5.991E-05 0.646 -0.015 2.120E-04 0.653 -0.007 4.570E-05 0.676 0.016 2.637E-04 0.653 -0.007 4.984E-05 SUM = 73.938 MEAN = 6.602E-01 Standard Deviation= 6.701E-04 Table 2: Excel Spreadsheet from Exercise 1- Statistical Analysis of Filter Paper, showing the standard deviations for the group data as well as the population data. Exercise 2- Graphing Exercise Concentration (μg/mL) Absorbance (AU) 5.0 0.124 10.0 0.243 20.0 0.486 30.0 0.712 Unknown 0.417 Table 3: The Concentration and the corresponding Absorbance values given
Image of page 5

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Absorbance vs. Concentration y = 0.0236x + 0.0079 R 2 = 0.9997 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.0 10.0 20.0 30.0 40.0 Concentration (μg/mL) Absorbance (AU) Absorbance Linear (Absorbance) Figure 1: Graph showing the linear regression line for Absorbance vs. Concentration, based on the known data points given in table 3 According to the Regression analysis from Figure 1, the line of best fit has the equation, y = 0.0236x + 0.0079, where x stands for concentration and y stands for Absorbance. 0.0236 is the slope of the regression line and 0.0079, the y-intercept.
Image of page 6
Image of page 7
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern