Practice Session 4

Practice Session 4 - 1 ECSE 462 PRACTICE SESSION IV...

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1 ECSE 462 PRACTICE SESSION IV Trigonometric Identities cos(A+B)=cosAcosB-sinAsinB cos(A-B)=cosAcosB+sinAsinB sin(A+B)=sinAcosB+cosAsinB sin(A-B)=sinAcosB-cosAsinB In Lecture 6, a current i a of the a-phase winding having an airgap B-field cos aa m Bi b θ = as shown in Fig. 1 90 ° 180 ° 270 ° 360 ° am ib B Fig. 1 can be represented by space vector a Φ . The space vector has a magnitude proportional to the current i a and is orientated in the direction of the winding axis. The space vectors of a-phase and b-phase can be summed vectorially as illustrated in Fig. 2. Fig. 2 a Φ a i N ϕ b i N b Φ N S T Φ +=
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2 a Φ JG represents cos aa m Bi b θ = b Φ represents cos( ) m b ϕ =− T Φ represents cos( ) TT BB ξ Question 1 Fig. 3 Fig. 3 shows the stator and rotor windings in the α β frame. The windings have 2-poles. The stator iron is stationary. The stator currents are: cos2 .60 sin 2 .60 s S s i t I i t π ⎡⎤ = ⎢⎥ ⎣⎦ Represent the B-field by a resultant stator flux vector S Φ . Show that the speed of rotation
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Practice Session 4 - 1 ECSE 462 PRACTICE SESSION IV...

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