HW2 solutions - Byers Raymond Homework 2 Due noon Inst J A...

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Byers, Raymond – Homework 2 – Due: Jan 30 2006, noon – Inst: J A Holcombe 1 This print-out should have 19 questions. Multiple-choice questions may continue on the next column or page – fnd all choices beFore answering. The due time is Central time. The grading on homework has been changed to allow more than one guess. Good luck! 001 (part 1 oF 1) 10 points Calculate ΔG r For the decomposition oF mer- cury(II) oxide 2 HgO(s) 2 Hg( ) + O 2 (g) Δ H f - 90 . 83 - - (kJ · mol - 1 ) Δ S m 70 . 29 76 . 02 205 . 14 (J · K - 1 · mol - 1 ) at 298 K. 1. +246.2 kJ · mol - 1 2. - 117.1 kJ · mol - 1 3. - 246.2 kJ · mol - 1 4. - 64.5 kJ · mol - 1 5. +117.1 kJ · mol - 1 correct Explanation: 002 (part 1 oF 1) 10 points The standard Free energy oF Formation oF CS 2 ( ) is 65.27 kJ · mol - 1 at 298 K. This means that at 298 K 1. CS 2 ( ) is thermodynamically stable. 2. No catalyst can be Found to decompose CS 2 ( ) into its elements. 3. CS 2 ( ) has a negative entropy. 4. CS 2 ( ) is thermodynamically unstable. correct 5. CS 2 ( ) will not spontaneously Form C(s) + 2 S(s). Explanation: 003 (part 1 oF 1) 10 points Consider the Following reaction: CO(g) + Cl 2 (g) COCl 2 (g) Species ΔH 0 f S 0 kJ/mol J/mol · K CO - 110 . 5 197 . 6 Cl 2 0 . 0 223 . 0 COCl 2 - 223 . 0 289 . 2 Calculate Δ G 0 For the reactions at 298 K. 1. - 500 . 0 kJ/mol 2. - 7 . 3 J/mol 3. - 73 . 34 kJ/mol correct 4. 221 . 1 kJ/mol Explanation: 004 (part 1 oF 1) 10 points A thermodynamically Favorable reaction 1. All choices are correct. correct 2. is called spontaneous but doesn’t neces- sarily proceed at a detectable rate. 3. has negative Δ G . 4. iF also kinetically Favorable, proceeds at a detectable rate. Explanation: A reaction is spontaneous (Favorable) when Δ G is negative. Just because a reaction is thermodynamically Favorable doesn’t mean that it proceeds Fast enough to be detected. Only when a reaction is kinetically Favorable can it be detected. 005 (part 1 oF 1) 10 points Evaluate Δ G 0 For the reaction 2 N 2 (g) + 3 O 2 (g) 2 N 2 O 3 (g)
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Byers, Raymond – Homework 2 – Due: Jan 30 2006, noon – Inst: J A Holcombe 2 at 25 C.
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HW2 solutions - Byers Raymond Homework 2 Due noon Inst J A...

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