experiment #9

experiment #9 - Experiment #9 Chemical Kinetics:...

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Experiment #9 Chemical Kinetics: Experimental Determination of a Rate Law Kevin Falting Chemistry 117 – 529 November 11 th , 2009 Lab Partner: Zach Thomas
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Summary: Experiment number nine, Chemical Kinetics: Experimental Determination of a Rate Law, has us performing the reaction between a compound called Crystal Violet [CV + ] and Hydroxide [OH - ] to make Crystal Violet Hydroxide or [CVOH]. In the reaction we use a dye molecule, Crystal Violet, and react it with hydroxide ions to form a colorless solution. The progress of this reaction can be determined by monitoring the color of the solution as a function of time after the reactants are mixed. What we are determining is the rate law for this reaction in the form rate = k[CV + ] m [OH - ] n , where k is the rate constant for the reaction, m is the order with respect to crystal violet, and n is the order with respect to the hydroxide ion. By measuring the effects of changes in the concentration of each reactant, I am able to determine the values for k, n, and m. We
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This note was uploaded on 02/23/2010 for the course CHEM 107 taught by Professor Generalchemforeng during the Fall '07 term at Texas A&M.

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experiment #9 - Experiment #9 Chemical Kinetics:...

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