dev12384 - x 2 + xy ) dy = 0. Question 2. 1. Use the xed...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
MAT 2384A-Fall 2009-Homework #1 To be submitted in class on Friday, September 25 Question 1. For each of the following ODEs, Find the General Solution. If an initial condition is given, find the corresponding particular solution. 1. y p 1 + y 2 y 0 = xe x , y (1) = 3 2. 4 xyy 0 + 3 x 2 + 2 y 2 = 0 , y (1) = 1 3. ( y 2 e xy 2 + 4 x 3 ) dx + (2 xye xy 2 - 3 y 2 ) dy = 0 4. (cos y + y cos x ) dx + (sin x - x sin y ) dy = 0 , y ( π/ 2) = π/ 4 5. (1 + y 2 ) y 0 = y cos x, y (0) = 1 6. ( 1 x - e y ) dx + (sin y - xe y ) dy = 0 , y (1) = 0 7. (2 xy 4 e y + 2 xy 3 + y ) dx + ( x 2 y 4 e y - x 2 y 2 - 3 x ) dy = 0 8. (3 xy + y 2 ) dx + (
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: x 2 + xy ) dy = 0. Question 2. 1. Use the xed point iteration method to nd the root of x 4 + 6 x-5 in the interval [0 , 1] to 5 decimal places. 2. Use Newtons Method to nd 3 7 to 6 decimal places. Start with x = 2 . 3. . Use Newtons Method to nd the positive solution of e x = 2cos x to 6 decimal places. Start with x = 1. 1...
View Full Document

This note was uploaded on 02/24/2010 for the course SITE MAT2384 taught by Professor Josephkhoury during the Fall '09 term at University of Ottawa.

Ask a homework question - tutors are online