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first practice solutions

# first practice solutions - 1 1 km 3(1000 m km 3(10 9 nm m)3...

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1. 1 km 3 (1000 m / km) 3 (10 9 nm / m) 3 = 10 36 km 3 2. barium nitride 3. 34.05871 / 2.78 = 12.251335 (which has three significant figures) 12.251335 + 0.31 = 12.561335 with one place beyond the decimal point 12.6 4. 6.0151 x + (7.0160)(1 – x) = 6.94 –1.0009 x = –0.076 x = 0.08 or 8% 5. h = V / A A = π r 2 = π ( 17.39 / 2) 2 cm 2 = 237.51 cm 2 V = m / d = 0.9720 g / (0.843 g/cm 3 ) = 1.153 cm 3 h = 1.153 cm 3 / 237.51 cm 2 = 0.00485 cm 6. 6.41 g S 8 0.02499 mol S 8 0.02499 mol P 4 3.10 g P 4 7. AB. 40.0 mol (2 mol ions / mol NaCl) = 80 mol ions AC. 30(3) = 90 mol AD. 20(4) = 80 AE. 20(2) = 40 BC. 20(3) = 60 BD. CH 3 OH is not ionic. Thus, the answer is AC. 8. 27.64 g O 1.7275 mol O (3 mol M / 4 mol O) = 1.295625 mol M 72.36 g M / 1.295625 mol M = 55.85 g / mol. 9. 15.00 g CO 2 0.3408 mol CO 2 ( 1 mol C / 1 mol CO 2 ) = 0.3408 mol C 4.093 g C 5.000 4.903 g = 0.907 g H 0.900 mol H C 0.3408 H 0.900 C H 0.900 / 0.3408 C H 8 / 3 C 3 H 8 10. CaCO 3 CaO + CO 2 27.0 g CaCO 3 0.2697 mol CaCO 3 (1 mol CaO / 1 mol CaCO 3 ) = 0.2697 mol CaO 0.2697 mol CaO 15.12 g CaO 14.2 g / 15.12 g = 0.939 or 93.9% 11. 1.286 g AgCl 0.008973 mol AgCl (1 mol MCl 2 / 2 mol AgCl) = 0.0044865 mol MCl 2 1.000 g / 0.0044865 mol MCl 2 = 222.9 g / mol MCl 2 222.9 2(35.45) = 152.0 g / mol M 12. HF is a weak acid in water. CH 3 NH 2 is a weak base in water (compare NH 3 ).

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first practice solutions - 1 1 km 3(1000 m km 3(10 9 nm m)3...

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