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# 402 - Announcements Wednesday April 2 2008 Homework...

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4/2/2008 1 Announcements: Wednesday, April 2, 2008 Homework WebAssign #12- Due Wednesday, April 9 at 8:00 AM Recitation Print Week 11- Solubility Equilibria AND Pre-Recitation! Lab Lab 8- Separation of Metal Ions Complete your prelab (p. 75) before recitation. Three week lab! Suggested Textbook Questions Begin reading Chapter 22.3, and working problems (see syllabus). Which of the following complex ions would increase the solubility of AgCl(s) the most? (Assume [CN - ] = [NH 3 ] = [S 2 O 3 2- ].) AgCl( s ) Ag + ( aq ) + Cl - ( aq ) K sp = 1.8x10 -10 March 31, 2008 - CT#3 B. Ag(NH 3 ) 2 + K f = 1.7 x 10 7 C. Ag(S 2 O 3 ) 2 3- K f = 4.7 x 10 13 D. Cannot tell A. Ag(CN) 2 - K f = 3.0 x 10 20 As long as the stoichiometry is the same (1:2) and the ligand concentrations are the same, K net = K sp xK f K f , K net Without doing the whole calculation, what is the solubility of AgCl(s) in the presence of 0.10 M CN - ? AgCl( s ) Ag + ( aq ) + Cl - ( aq ) K sp = 1.8 x10 -10 Ag + ( aq ) + 2CN - ( aq ) Ag(CN) 2 - ( aq ) K f = 3 x10 20 April 2, 2008 - CT#1 A. 2.3 x 10 -8 C. 2.3 x 10 5 B. 0.05 K net = K sp x K f = [Ag(CN) 2 - ][Cl - ]/[CN - ] 2 5.4 x 10 10 = x 2 /(0.10-2x) 2 Square root both sides: 2.3 x10

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