This preview shows pages 1–12. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: Gene mapping in humans Linkage mapping Steps in human recombination mapping Examine progeny of a crosses in families Determine those that are recombinant (R) and those that are nonrecombinant (NR) Based on observed R and NR in each family estimate the most probable rate of recombination as an estimate of linkage 2 Reasons human mapping is different Cannot do test crosses in humans Cant always determine unambiguously if progeny are recombinant Small families so number of recombinants low Can be hard to find Must rely on statistics of small numbers 3 First problem  which child is a recombinant in a family Must determine, from pedigrees, who is recombinant The biggest problem is determining phase in the parents 4 First problem  which child is a recombinant in a family Must determine, from pedigrees, who is recombinant The biggest problem is determining phase in the parents 4 D A d a D a d A D AND A in cis D AND A in trans So in this pedigree it is pretty simple to decide that there are two recombinant children Human linkage mapping A 2 A 1 B 2 B 1 A 2 A 1 B 2 B 1 A 1 A 1 B 1 B 1 A 1 A 1 B 2 B 1 A 2 A 1 B 2 B 1 A 1 A 1 B 1 B 1 A 2 A 1 B 1 B 1 A 2 A 1 B 2 B 1 So in this pedigree it is pretty simple to decide that there are two recombinant children Human linkage mapping A 2 A 1 B 2 B 1 A 2 A 1 B 2 B 1 A 1 A 1 B 1 B 1 A 1 A 1 B 2 B 1 A 2 A 1 B 2 B 1 A 1 A 1 B 1 B 1 A 2 A 1 B 1 B 1 A 2 A 1 B 2 B 1 The A 2 B 2 must have come from the fathers chromosome and A 1 B 1 came from mother and are cis So in this pedigree it is pretty simple to decide that there are two recombinant children Human linkage mapping A 2 A 1 B 2 B 1 A 2 A 1 B 2 B 1 A 1 A 1 B 1 B 1 A 1 A 1 B 2 B 1 A 2 A 1 B 2 B 1 A 1 A 1 B 1 B 1 A 2 A 1 B 1 B 1 A 2 A 1 B 2 B 1 The A 2 B 2 must have come from the fathers chromosome and A 1 B 1 came from mother and are cis So in this pedigree it is pretty simple to decide that there are two recombinant children Human linkage mapping A 2 A 1 B 2 B 1 The A 2 B 2 must have come from the fathers chromosome and A 1 B 1 came from mother and are cis 6 Please answer this question without talking to your neighbor Please dont whisper or share answers for this question, we promise you will get a chance to talk to your neighbor!! Human linkage mapping One person for this dominant trait in generation III is recombinant  who?...
View
Full
Document
This note was uploaded on 02/25/2010 for the course MCDB 2150 taught by Professor Winey,mark during the Spring '06 term at Colorado.
 Spring '06
 WINEY,MARK

Click to edit the document details