159_fall_07_chapt_11_supplement

159_fall_07_chapt_11_supplement - Chapter 11 Theories of...

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Ch 11 1 Chapter 11 Theories of Covalent Bonding
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Ch 11 2 Theories of Covalent Bonding 11.1 Valence Bond (VB) Theory and Orbital Hybridization 11.2 The Mode of Orbital Overlap and the Types of Covalent Bonds 11.3 Molecular Orbital (MO)Theory and Electron Delocalization
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Ch 11 3 Another Figure - Hybridization of CH 4
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Ch 11 4 Typical Exam Problem 34 Which of the following is most likely to involve sp 3 d hybrid orbitals on the central atom? X. SF 4 Y. CF 4 Z. ClF 4 - AB. X only BC. X and Z AC. Y only BD. Y and Z AD. Z only BE. X, Y, and Z AE. X and Y CD. None of them
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Ch 11 5 Solution to Typical Exam Problem 34 SF 4 has a trigonal bipyramidal arrangement of electron pairs around the central atom. (The shape of the molecule is sea-saw). There are four bond pairs and one lone pair on S, which uses sp 3 d hybrids. CF 4 is tetrahedral; sp 3 hybrids are used. ClF 4 - 7+4(7) + 1 = 36 electrons. 36/2 = 18 electron pairs to be placed on the structure. There are four single Cl-F bonds and two lone pairs on the central atom, Cl. Therefore sp 3 d 2 hybrids are used.
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Ch 11 6 Typical Exam Problem 33 Which of the following statements is false regarding the reaction NH 3 + BF 3 -- Æ H 3 N-BF 3 ? W. The molecular geometry around nitrogen changes X. The molecular geometry around boron changes Y. The hybridization of boron changes Z. The hybridization of nitrogen changes AB. W only BD. W and Y AC. X only BE. W and Z AD. Y only CD. X and Y AE. Z only CE. X and Z BC. W and X DE. Y and Z
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Ch 11 7 Solution to Problem 33 Only the hybridization of N does not change. There are four bond pairs around N in the product; tetrahedral arrangement of electron pairs implies sp 3 hybrids. In NH 3 , there are three bond pairs, and one lone pair, so the electron pair arrangement is tetrahedral , and the hybrids are
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159_fall_07_chapt_11_supplement - Chapter 11 Theories of...

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