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Unformatted text preview: UF-ESI-6314DMOR-03-01.xmcdpage 1 of 403-01.Consider the following set of equations.x1x2+x3-1=(1)x12x2+3=(2)2x2x3+x4+3=(3)Part A:Calculate all extreme points of the feasible region given by those constraints, along withthe restrictions that:xDo this by choosing every possible set of basic variables and solving three equations in threeunknowns (not by graphing).By definition, a nonbasicvariable must be zero. To solve this problem requires rotating througheach of the four variables and making it nonbasic so as to solve for the other three.Work backwards by setting each variable equal to zero beginning with:x4=This means that:x1x2+x3-1=x12x2+3=2x2x3+3=which reveals each variable as:x111=This represents a feasiblesolution because it meets the given constraints.Luther Setzer1 NASA Pkwy E Stop NEM3, Kennedy Space Center, FL 32899(321) 544-7435UF-ESI-6314DMOR-03-01.xmcdpage 2 of 4Now do the same with the next variable:x3=This means that:x1x2+1=x12x2+3=2x2x4+3=which reveals each variable as:...
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- Fall '09