formulas for quiz 3

formulas for quiz 3 - T(K = t(°C 273.15 ∆ E = q w w =...

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1 L atm = 101.325 J R = 0.08206 L atm / mol K R = 8.3145 J / mol K PV = nRT R h c = 2.18 x 10 –18 J R = 1.097 x 10 7 m –1 c = 3.00 x 10 8 m/sec 760 mm Hg = 1 atm F = ma 1 N = 1 kg m/sec 2 1 J = 1 N m h = 6.626 x 10 –34 J sec rate α u rms u rms = (3RT / M) 1/2 (E k ) average = (3/2)(R / N A )T E = (3/2)nRT n = N / N A n = m / M
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Unformatted text preview: T(K) = t(°C) + 273.15 ∆ E = q + w w = –P external ∆ V H = E + PV ∆ H = ∆ E + ∆ (PV) q = ms∆T q = C∆T λ = h / mc λ = h / mv h ν = φ + (1/2)mv 2 v ≡ u = speed E = hν c = λν E n = –R h c Z 2 / n 2 (∆x)(m∆v) ≥ (h/4π) N A = 6.022 x 10 23 mol –1...
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This note was uploaded on 04/03/2008 for the course CHEM 159-160 taught by Professor Zbaida during the Fall '07 term at Rutgers.

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