HW2 - P I 2 Two gage marks are placed exactly 250 mm apart...

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Unformatted text preview: ,__ P I 2.] Two gage marks are placed exactly 250 mm apart on a 12-mm—diam ' romem 2 1 aluminum rod. Knowing that, with an axial load of 6000 N acting on the rod‘ettfi‘: i} distance between the gage marks is 250.18 mm, determine the modulus of elastic-mr - of the aluminum used in the rod. ' g = AL = L — to r 250. IS - 150.00 = o. '18 mm ‘5 _ $5M!” . _ E : T ' agourim “ 0' 00°72 _... T .1 , _£ 3. A r if J2 r a," (in) = i13-0‘?7 hm" = [1103? #0 M P 600 o 6 2 if = = 53-05?“ ’0" Pa- 6“ 53 05:2 XJO‘ 1 a ' :—-—_~———'—-—-———-—=__¢|OP E=3.GP : E 8 0.00071 73 68 5‘ .a 7 7 CL «III- I _._....________.__......_.__...._. ! Problem 2.3 2-8 80411-10118 wire ofS-mm diameter is made ofa steel with Ea an ultlrnate tensfle strength of 400 MPa. If a factor of safet H 200 G determine (a) the largest allowable tension in the Wife 5 y of 3'2 [5 dc: elongation of the wire. ’ ( ) the Correspom.‘ CL 2' DO 6 -— _' _ 7. H 6“ L’ “a 9“ A'fidl—Ef51=rre.essw‘~ ' {9.7535 No"- R): GLA a [400xl0‘)(1?. gums“) r 725% N I a R) 725% PM" . ' 3.1 Re can 5: PL—W __ _ --3 AE (immSHFO-cjcgooxiog) :: 50,03“) 1m 5-2500an w :' N Pay”: 2.145 kw Problem 217 2.17 Two solid cylindrical rods are joined at 3 and loaded as shown. Rod AB is made of steel (E = 200 (We) and rod BC of brass (E = 105 GPa). Determine (a) the total deformation of the composite rod ABC, (2:) the deflection of point B. P = 30 MN Real AB: FAB = -*P -— -30KH03N 30mm Lm : 0.2mm as : 200x10“ 5P9. 40“” titJma = 14(30):: "£06,85th : 705-33xxd‘m‘ 30x 03} 0.150} 50mm 3”: M — _%* Em; A” ' (200 XIDQ}(706.3‘SX to") -53. 052x10“ w E”! BC: PM: Bow-10 = 70 Ma r 70x10! N H L54 - 9.300;“ EEC.— [05x {9* Pa Add = 3050)“ = 1.9e35xzo3mm‘= League“; 8 1. Far. LB: h (?O¥103](O-goo\ 6L _____ “ _' Eat/Ago (Ios‘x tO‘XtfléSS’tlo" ~ -101- 8551 Ha“ m (at) T041“? plepowma+tnont (la) 54.5-1- : 8AB+ SQ; : “IsLi-qytlfc'm 1' "GJSHctr-nm“ DCP}80+;091 o? Eofm+ B, 53: Sat 58: OJth mm ‘k"‘ Problem 2 20 2.20 ThejodABC is made of an aluminum for which E = 70 GPa. Knowin = 6 kN and Q = 42 kN, determine the deflection of (a) point A, (b) pointg, P ____ A I 1 Ti ’- -c 1. 1 Am = q 3% .- ‘q(0.020) -‘- 3H. M We: m 20-mmdiameler AM. : : 15":0‘060}1 T 2' KID-3 m2 0.4m ¢ P PM :- P = 6 V103 N r Pg; : P- Q = gm?— wuo‘r -39.!0“ N '_ w dj t Lara : 0.4M Lac: 0-5- M 1 8A : PflLm _, (leofiflo-q) Q a AME. (3I4.Jé>'!0")(?ovro“) _ :- IOfiJfi-S'W" ° W l a. g = P5CLB¢_ (rseuobflofii EC. A515 (2.32?‘f'yf§3r7o Hoe) : " filo-.ql'f7 VIC—5 :41 (an 3a = Sm + 55.1 r W. i3§*i6‘-¢io.747xzd‘m r Jamie" M = 0.01851 9mm? '4 3L3 -' 5:3; 1 - ?o-G¥ *{O-‘ M = "' MM 0" 0. OCH“? mm 1! '4 Problem 2.26 2.26 Each of the links AB and CD is made of steel (E = 29 x 10" psi) and . . l . . his; umform rectangular cross secuon of 4 x l m. Determme the largest load win. can be suspended from point E if the deflection of E is not to exceed [101 m = O Arenarfinki A:(—‘q)(r)= 0.251? = O LequH: L = 8 Eh. . _ HQL _ 0.5me _ , _ .c ———~—-————DeF°pm“+'°M‘ 5‘3" EA - L'MHO‘MOJS) ‘ I'Ebfiwo P 8:13 e L" L ‘ gz'gmfim = 2.7586540”- P E ' (Rfix:06\(Q253 DeHml-om. Pad 8. 53-. 5% 53: i.css:z»:o"m Pond C. St = 8m 5: = 2.75%esro'WL Geomehét eanaa. 5 c ” SB ‘ ‘= . g5 Pawn—1H (5';n.———»4 e = 3:1: Sc : Leg-fl no“ Tc; gnsgexmlp = O.HUI3SHD‘C P gs = SF + che = 9.75.86ufo'6P1-(153(ofl‘fI33xJO-‘P)= amaswd‘f’i UAflI-Je a"? 5.5: 5.9 7 0.01;“. Limknj mice a? ? 9.3793H0"P = 0.0: P: 104; ,9}; P: Loss ka5 4 ‘\ 2.27 Each of the links AB and CD is made of aluminum (E = 75 GPa) and has a Cross-sectional area of 125 mm}. Knowing that they support the rigid member BC, determine the deflection of point E. EB Fan USE mam her BC as q. 'F'PQQ. C 8 5)::03'N — (can) as + (o.qq)c$x:o’ )= o F”, = 3.4315323!" M 1—1:, = 1.5625 H03 u I 2MB = o '. (0.6.4) Fan “ (O-Q‘JKQ‘IOS ) .- 0 pp» ,Praks AB anal an, A= ii25'mm1 = 120104.." a 3 ' =W : 1310:: do“ m = 5e- (15%]qu +25‘x l0“) - L—L—"5‘25*03)(0’36) = £0.00x104m 3 SC. (75xlo‘x lu'xlo" ) _éu _ Sg—S: _ 72-00 “lb 549.0le 9 “ —'—“Ek — 'O-é‘h = 112.5 No" m! 51?: Sc+ PR6 = 60.00 no“ 4- (0.49 XML: no“) SE:O,IOq5‘MML -‘ gm”. = lo‘?..5' >40" in ...
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  • Spring '08
  • LINDASCHADLERFEIST
  • Trigraph, solid cylindrical rods, largest allowable tension, OJth mm ‘k, ultlrnate tensfle strength, wire ofS-mm diameter

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