HW3_p.6 solution

HW3_p.6 solution - 1.3.6.1.4.1 internet private enterprise...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
1. Define Scalar Object Ans: Scalar object defines a single object instance while tabular object defines multiple related object instances that are grouped in MIB tables. 2. Define Columnar object Ans: The SNMP supports operations on MIB objects whose syntax is ObjectSyntax as defined in the SMI. Informally stated, SNMP operations apply exclusively to scalar objects. However, it is convenient for developers of management applications to impose imaginary, tabular structures on the ordered collection of objects that constitute the MIB. Each such conceptual table contains zero or more rows, and each row may contain one or more scalar objects, termed columnar objects. 3. What is the full OID, both numeric and in text for sys Descr.? Ans: Numeric: 1.3.6.1.2.1.1.1.0 Test: iso(1) org(3) dod(6) internet(1) mgmt(2) mib-2(1) system(1) sysDescr(1) 0 4. What enterprise numbers have been assigned for
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 2
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 1.3.6.1.4.1 internet private enterprise Ans: General Dynamics C4: 576 Cisco: 9 Northern Telecom (NORTEL): 562 IBM: 2 Hewlet Packard: 11 AT&T: 74 5. What is the highest enterprise number that has been assigned? Ans: Securaplane Technologies: 28898 (This is the latest information I can find. It may change as time passes) 6. What is the minimum time for a ARP response on a 1 Gbps Ethernet? ARP Ethernet frame = 512+64 = 576 bits Transmission delay: tx T = 9 10 * 1 576 = 576 ns Assume the distance between sender or receiver to the switch is 100 meters Propagation delay: 8 10 * 2 100 = p T = 500 ns Processing delay: 100 = s T ns (for typical switch) The minimum end-to-end delay = tx T + 2 p T + s T =1676 ns = 1.676 s The minimum time for an ARP response since sending out the request = 2*1.676 = 3.352 s...
View Full Document

This note was uploaded on 02/26/2010 for the course SIS Telcom 212 taught by Professor Kabara during the Spring '10 term at Pittsburgh.

Page1 / 2

HW3_p.6 solution - 1.3.6.1.4.1 internet private enterprise...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online