Discussion4

Discussion4 - Discussion 4 Emily Mower February 17, 2010...

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Unformatted text preview: Discussion 4 Emily Mower February 17, 2010 Topics to be covered: Survivors guide: pages 6-8 Description of mixed random variables Software error vs. maintenance costs Textbook problem 2.100 1 1 Survivors Guide 1.1 Inequalities and Their Graphs The best way to think about how to deal with inequalities is to figure out where the function is zero. Then plug in values on either side of this line to figure out which side to shade. See Figures 1 and 2 for examples. Figure 1: An example of the graphical depiction of inequalities . Figure 2: An example of the graphical depiction of inequalities . 2 1.2 Series Expansions Lets start with the finite series: a + ar + ar 2 + ... + ar n- 1 Let s = 1 + r + r 2 + ... + r n- 1 Thus, rs = r + r 2 + r 3 + ... + r n Subtract rs from s : s- rs = 1- r n Rearrange to solve for s: s = 1- r n 1- r Multiply by a factor, a: as = a- ar n 1- r Thus, for the finite series: a + ar + ar 2 + ... + ar n- 1 we can say: a + ar + ar 2 + ... + ar n- 1 = a- ar n 1- r When a = 1, this simplifies to: 1 + r + r 2 + ... + r n- 1 = 1- r n 1- r Lets now look at the infinite series: a + ar + ar 2 + ... If | r | < 1 , then as n : a + ar + ar 2 + ... = a 1- r , | r | < 1 When a = 1, this simplifies to: 1 + r + r 2 + ... = 1 1- r , | r | < 1 Lets differentiate the infinite series: 1 + r + r 2 + r 3 + ... D (1 + r + r 2 + r 3 + ... ) = 1 + 2 r + 3 r 2 + r 3 + ... = D ( 1 1- r ) = 1 (1- r ) 2 , | r | < 1 3 Lets differentiate the finite series: 1 + r + r 2 + r 3 + ... + r n D (1 + r + r 2 + r 3 + ... + r n- 1 ) = 1 + 2 r + 3 r 2 + r 3 + ... + nr n- 2 = D ( 1- x n 1- x ) = nr n- ( n + 1) r n- 1 + 1 (1- r ) 2 Now lets look at e . In 1683, Johann Bernoulli defined e as: e = lim n (1 + 1 n ) n e x = lim n (1 + x n ) n If we want develop an expansion of the e or e x we need to use the binomial theorem....
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Discussion4 - Discussion 4 Emily Mower February 17, 2010...

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