2006-Spring-Final_s

# 2006-Spring-Final_s - 1(22pts = 4 3 2 2 4 3 2 2(a x1 = 45...

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1. (22pts = 4 + 3 + 2 + 2 + 4 + 3 + 2 + 2) (a) x 1 = 45 ; x 2 = 42 : 6 ;s 1 = 1 : 225 ;s 2 = 1 : 140 ;s p = q s 2 1 + s 2 2 2 = 1 : 183 H 0 : 1 2 = 0 ;H a : 1 2 6 = 0 ;t = x 1 x 2 s p p 2 = 5 = 3 : 207 > 2 : 3060 = t 0 : 025 ; 8 . Reject H 0 and conclude that the average hourly production from two machines are di/erent. (b) 0.01 < p-value < 0.02 (c) Both populations normal and equal variance (d) x 1 x 2 ± t 0 : 025 ; 8 s p p 2 = 5 or 2 : 4 ± 1 : 726 e. D = 2 : 4 ;s D = 0 : 894 D = 1 2 H 0 : D = 0 ;H a : D 6 = 0 ;t = D s D = p 5 = 6 : 00 > 2 : 7764 = t 0 : 025 ; 4 : Reject H 0 and conclude that the average hourly production from two machines are di/erent. f. p-value < 0.01. g. The di/erence D follows normal distribution h. D ± t 0 : 025 ; 8 s D p 5 or (1.289, 3.511) 2. (14pts = 2 + 3 + 3 + 3 + 3) (a) H 0 : = 100 ;H a : 100 (b) ± = 0 : 01 : lower chance of declare emergency when, in fact, pollution level is at safe range. (c)

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## This note was uploaded on 02/27/2010 for the course ISOM ISOM111 taught by Professor Anthonychan during the Spring '09 term at HKUST.

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2006-Spring-Final_s - 1(22pts = 4 3 2 2 4 3 2 2(a x1 = 45...

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