fin05sol - ISMT 111 Fall 05 Final Exam Suggested solution...

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5 ISMT 111 Fall 05 Final Exam Suggested solution Question 1: (a) The Hypothesis statement is H 0 : μ =23 vs H 1 μ >23. Naturally we need to assume that that either the data are normally distributed in which case we assume that the CLT applies. The sample size n=56 is large enough and we can use the Z-test and the test statistic is Z= 56 (23.5 – 23)/10.2=.367. We can use the normal table to find the critical value of 1.645 at alpha =.05. In this case since .367<1.645 we cannot reject the null hypothesis and must conclude that the evidence indicates that their claim is false. (b) The 95% confidence interval is approximately 23.5 ± 2.67 (c) To find A, solve the equation 56 (23.5 – A)/10.2 1.645, the solution is A 21.258. Hence set A=21. Note: Question (c) can be adjusted for different values of the standard deviation. Question 2: (a) Using the formula for the differences where the population variances are assumed equal but unknown and the populations are normally distributed.
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fin05sol - ISMT 111 Fall 05 Final Exam Suggested solution...

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