Solutions_Manual_for_Organic_Chemistry_6th_Ed 36

Solutions_Manual_for_Organic_Chemistry_6th_Ed 36 - 2 -5 (a)...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 2 -5 (a) linear, bond angle 1 80° •• •• (b) all atoms are sp3 ; tetrahedral geometry and bond angles of 1 09° around each atom not a bqnd-;-shows not a bond-s how s '. H H lone Rair coming \ • , � � lbon� pair gomg ehmd paper "'--- / out 01 paper I I H , ....... 0 , ..... H H-C-O-C-H C C" I I A '" l, H H HH HH (c) all atoms are sp3 ; tetrahedral geometry and bond angles of 1 09° around each atom H H H .. H �'C ..... H / " H - C - N - C" H / I I ......-- not a bond-shows H H C H '-... N '/ . lone pair going behind paper /1 H H' H C /' , " " . J '=:.," C-H H H J \H H (d) trigonal planar around the carbon, bond angles 1 20°; tetrahedral around the single-bonded oxygen, bond angle 109° :0: 3 II ,.....-- · 0 · . I I . r sp C" I H all atoms in one plane / H °/ sp2 H - C - O - H •• •• o == C == o + + S+p2 Sp Sp2 •• •• � •• •• .. •• (e) carbon and nitrogen both sp, linear, bond angle 1 80° H - C N: (0 a ll three atoms in a line trigonal planar around the sp2 carbons, bond angles 1 20°; around the sp3 carbon, tetrahedral geometry and 1 09° angles sp2 H 1\ H H \C == C/ I H - C - C == C - H H I H I H I H/C " \,' H sp3 H / \ H (g) trigonal planar, bond angle about 1 20° •• .0. == .0.- .0.· + •• - of ozone shows that BOTH end oxygens must be sp 2_ see Solved Problem 2-8) 26 ( the other resonance form ...
View Full Document

This note was uploaded on 02/27/2010 for the course CHEM 140 taught by Professor Wade during the Spring '10 term at Whitman.

Ask a homework question - tutors are online