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Solutions_Manual_for_Organic_Chemistry_6th_Ed 102

Solutions_Manual_for_Organic_Chemistry_6th_Ed 102 - 5Å35...

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5-34 (b) Rotation of the enantiomer will be equal in magnitude, opposite in sign: -15.90°. (c) The rotation -7.95° is what percent of - 15.900? - 7 9 5 ° -- ' - x 100% = 50% e.e. - 15.90° There is 50% excess of (R)-2-iodobutane over the racemic mixture; that is, another 25% must be R and 25% must be S. The total composition is 75% (R)-(-)-2-iodobutane and 25% (S)-(+)-2-iodobutane.
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Unformatted text preview: 5Å35 All structures ²n this problem are ch²ral. C al H + Oh H + OH cH20H A chO HO ± H HO ² h ch20H Æ enan¿²oÇersÈ A and ÆÉ C anD D cHO h ³ Oh hO ´ H cH2±H C D²astereOMers: A and C; A anD D; ÆaÊd C; Æand D (b¸ E F G enantIOmers: E anD F± G anD H DIastereoMersË E and G± E anD H± F and G± F and H 95 cHo HO µ h h ¶ oh ch2±H D H...
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