Solutions_Manual_for_Organic_Chemistry_6th_Ed 302

Solutions_Manual_for_Organic_Chemistry_6th_Ed 302 - 13-45...

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Unformatted text preview: 13-45 (a) CH CH \ / C=C / \ CH H Isomer A b d CH CH \ CC / CH H c a isomer A a = 8.2 (quaRtet, 1h) b = 8 17 (snglet, 3H) c = 8 16 (sNgLet, 3H d = 8 1 (doubLet, 3H) + H CH \ / CC / CHCH isOmer B d f H CH \ / CC / H CHCH d e g isOmer B d = 847 (sNgLet, ) e = 820 (quarTet, H) F 8 17 (snglet, 3H) g = 10 (tpLet, 3H) (b WT a as base, te MOre gy substtUted alkene, isomer a, would be expected To pedomnAEte ZaTsev ule Wt K--Bu as a ndered, buLy base, te Less sUbsttUTed aleNe, isOmer B wouD PredOmnaTe (Te HOMaNN prOucT) 1346 "uclear wasTe" s cOMpsed OF radOactve prodUcts from eter NUclear reactons, for eXamp FrOM elecTcal geNeraTNg sTaTONs pOwered by nUclear reactors, or resdUe FrOm medcaL or scentFc sTUdes sNG radOacTVe Ncldes as TeraeuTc aGents (le odne FOr tyrod TreatMeNt or as mOLecular tracers...
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This note was uploaded on 02/27/2010 for the course CHEM 140 taught by Professor Wade during the Spring '10 term at Whitman.

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