240_quiz2b - & ! $’ ! & ! ( ! ) $ ) ’ i 3 +-54V...

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Name __solution____________ ECE 240 – Quiz #2 February 4, 2010 For the circuit shown above, find: a. i 1 b. i 2 i 3 = 54 6 = 9 i 4 = 10 10 + 10 (9) = 9 / 2 i 2 = 12 12 + 6 (9 / 2) = 3 i 1 = 3 3 + 6 (3) = 1 + - !"# $% ! " ! $ !
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Unformatted text preview: & ! $’ ! & ! ( ! ) $ ) ’ i 3 +-54V 10 ! 4 ! 1 ! 6 ! 12 ! 6||3 = 2 i 2 +-54V 10 ! 1 ! 6 ! 12||6=4 +-54V 10||10=5 1 ! i 3 i 4 i 4...
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This note was uploaded on 02/27/2010 for the course ECE 240 taught by Professor Drsharlenekatz during the Spring '10 term at CSU Northridge.

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