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Unformatted text preview: Page 4 of 4 Problem 8 In the circuit shown in Figure P8, determine the terminal voltage of the source, the power supplied to the circuit (or load), and the efficiency of the circuit. Assume that the only loss is due to the internal resistance of the source. Efficiency is defined as the ratio of load power to source power. Figure P8. Solution : 0, , (using Ohm's law) 12 1 mA 12 7 1 mA 7 . S S T T T L T S S T L T S T S T T L T KVL V R I V V R I V R I R I V V I R R k V R I k V+ + = = ∴+ + = ⇒ = = = + Ω ⇒ = = Ω× = ( ) 2 2 2 3 7 7 mW 7 10 12 V 1 mA 12 mW R T L L L VS S T V V V P R R P V I = = = = × Ω = = × = Recall that the negative sign for the source power means that the source is supplying power. Therefore, the supplied power is 12 mW. The efficiency is given by 7 mW 0.5833 58.33% 12 mW L S R out in V P P or P P η = = = = . Ω = Ω = = k 7 k 5 V 12 L S S R R V...
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 Spring '08
 marks
 Electromotive Force, Volt, Watt, Kirchhoff's circuit laws

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