HW_6-Solutions-enme350

HW_6-Solutions-enme350 - ENME 350 Homework#6 Solutions...

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ENME 350 Electronics & Instrumentation I Homework #6 - Solutions Page 1 of 8 Problem 1 (4.3 from textbook) Solution
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ENME 350 Electronics & Instrumentation I Homework #6 - Solutions Page 2 of 8 Problem 2 (4.17 from textbook) Solution (a) From the continuity of the capacitor voltage:
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ENME 350 Electronics & Instrumentation I Homework #6 - Solutions Page 3 of 8 Problem 3 (4.37 from textbook) Solution
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ENME 350 Electronics & Instrumentation I Homework #6 - Solutions Page 4 of 8 Problem 4 For the circuit of Figure P4.37, determine an expression for the voltage across the inductor ( ) L V t and sketch over 0.2 1.0 t - ≤ ≤ s. Solution ( ) L L di V t L dt = ( ) exp( / ) L i t A t B τ = - + (0 ) (0 ) 0 L L i i + - = = (from continuity of current) 0 A B ∴ + = ( ) 2 L i t B → ∞ = = (from circuit in steady state, inductor becomes a short circuit) 2 B ∴ = and 2 A = - ( ) 2 2exp( / ), 0 L i t t t = - - , 1 0.2 s 10 10 5 eq L L R = = = = ( ) 2 2exp( 5 ), 0 L i t t t = - - ( ) 1 10exp( 5 ) 10exp( 5 ), 0 L L di V t L t dt t t = = × - = -
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ENME 350 Electronics & Instrumentation I Homework #6 - Solutions Page 5 of 8 Problem 5 The circuit of Figure P5 is a simple model of an automotive ignition system. The switch models the “points” that switch electric power to the cylinder when the fuel-air mixture is compressed. And R is the resistance between the electrodes (i.e., the “gap”) of the spark plug. Determine the value of
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This note was uploaded on 02/27/2010 for the course ENME 271 taught by Professor Marks during the Spring '08 term at Maryland.

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HW_6-Solutions-enme350 - ENME 350 Homework#6 Solutions...

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