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EE_331Sp_2009_-_HW5S

# EE_331Sp_2009_-_HW5S - EE 331 Devices and Circuits I...

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1 EE 331 Devices and Circuits I Spring 2009 Problem #5 Solution 3.100 ( a ) V dc   V P V on   15 2 1   20.2 V ( b ) C = I V r T 2 20.2 V 0.5 1 0.25 V 1 120 s 1.35 F ( c ) PIV 2 V P 2 15 2 42.4 V ( d ) I surge = CV P 2 60   1.35 15 2 10800 A ( e ) T 1 2 V r V P 1 2 60   2 .25   15 2 0.407 ms | I P I dc T T 20.2 V 0.5 1 60 s 1 0.407 ms 1650 A 3.101 ( a ) V dc   V P V on   9 2 1   11.7 V ( b ) C = I V r T 2 11.7 V 0.5 1 0.25 V 1 120 s 0.780 F ( c ) PIV 2 V P 2 9 2 25.5 V ( d ) I surge = CV P 2 60   0.780 9 2 3740 A ( e ) T 1 2 V r V P 1 2 60   2 .25   9 2 0.526 ms | I P I dc T T 11.7 V 0.5 1 60 s 1 0.407 ms 958 A 3.105 The circuit is behaving like a half-wave rectifier.

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EE_331Sp_2009_-_HW5S - EE 331 Devices and Circuits I...

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