Experiment 6 - and C 5 = 0.0000018 and l = 0.035 and...

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Experiment -6 AIM: Calculate for pure silica fibers- a) Graph for refractive index (n) with wavelength (λ) b) Graph for dn/dλ with wavelength (λ) c) Graph for d 2 n/dλ 2 with wavelength(λ) d) Graph for material dispersion (Dm) with wavelength e) Calculate material dispersion (Dm) at given wavelength f) Find Zero material dispersion wavelength Input required Boundary limits for inputs Formula Expected output Units n C 0 and C 1 and C 2 and C 3 and C 4 and C 5 and l and λ C 0 = 1.4508554 and C 1 = -0.0031268 and C 2 = -0.0000381 and C 3 = 0.0030270 and C 4 = -0.0000779
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Unformatted text preview: and C 5 = 0.0000018 and l = 0.035 and 0.65m< <1.65m C 0 + ( C 1 2 ) + ( C 2 4 ) + C 3 /( 2-l) + C 4 /( 2-l) 2 + C 5 /( 2-l) 3 1.456 to 1.4 unit less dn/d n 0.65m< <1.65m First order differential of n 0 to -0.01 m-1 d 2 n/d 2 n 0.65m< <1.65m Second order differential of n 0.1 to -.02 m-2 Dm and c and n 1.1m < < 1.7m and c = 3*10 5 km/s- ( / c) * ( d 2 n / d 2 ) * 10 9-20 to 20 ps/km.nm...
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This note was uploaded on 03/01/2010 for the course ELECTRONIC 12345 taught by Professor Xyz during the Summer '10 term at Punjab Engineering College.

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