Unformatted text preview: Physics 225/315 January 9, 2008 45 degree Linear Polarization and Circular Polarization 1 45o = (x + y ) 2 1 R = (x + iy ) 2 A polaroid sheet has its transmission axis at an angle with the x direction. What is the amplitude for light transmissiion through this Polaroid? We must project on the state representing the Polaroid.  = cos x + sin y For 45 degree Linear Polarization the amplitude is 1 45o = (cos x + sin y) (x + y ) 2 We use xx = 1 yy = 1 xy = 0 1 45o = (cos + sin ) 2 The magnitude squared of the amplitude is  45o 2 = 1 1 (1 + 2 sin cos ) = (1 + sin 2) 2 2 For Circularly polarized light R the amplitude is 1 R = (cos x + sin y) (x + iy ) 2 1 R = (cos + i sin ) 2 1 R = expi 2 The magnitude squared of the amplitude is  R 2 = So the intensity does not depend on . 1 2 1 ...
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This note was uploaded on 03/01/2010 for the course PHYSICS 225 taught by Professor Rothberg during the Spring '10 term at University of Washington.
 Spring '10
 ROTHBERG
 Light, Polarization

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