circpol - Physics 225/315 January 9 2008 45 degree Linear...

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Unformatted text preview: Physics 225/315 January 9, 2008 45 degree Linear Polarization and Circular Polarization 1 |45o = (|x + |y ) 2 1 |R = (|x + i|y ) 2 A polaroid sheet has its transmission axis at an angle with the x direction. What is the amplitude for light transmissiion through this Polaroid? We must project on the state representing the Polaroid. | = cos x| + sin y| For 45 degree Linear Polarization the amplitude is 1 |45o = (cos x| + sin y|) (|x + |y ) 2 We use x|x = 1 y|y = 1 x|y = 0 1 |45o = (cos + sin ) 2 The magnitude squared of the amplitude is | |45o |2 = 1 1 (1 + 2 sin cos ) = (1 + sin 2) 2 2 For Circularly polarized light |R the amplitude is 1 |R = (cos x| + sin y|) (|x + i|y ) 2 1 |R = (cos + i sin ) 2 1 |R = expi 2 The magnitude squared of the amplitude is | |R |2 = So the intensity does not depend on . 1 2 1 ...
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This note was uploaded on 03/01/2010 for the course PHYSICS 225 taught by Professor Rothberg during the Spring '10 term at University of Washington.

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