s03 - Solution to Problem 3 Congratulations to this week's...

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Solution to Problem 3 Congratulations to this week’s winners Kevin Bourrillion, Jon Dickmann, Robert Krause, Daniel Reeves. who will share the prize of $5.00. (Hey, it’s a buck and quarter more than you had yesterday!) There were 17 solutions received. Correct solutions were also received from Joshua Beenders, Dan Bradshaw, Jennifer Chong, John Dahlstrom, Jeff Decker, Mike Fitzpatrick, Mike Lepley, Steven Noto, Matt Rickert, Joshua McMinn, Tyler Scarlata and two from Math Department faculty! (They can play, but they can’t win!) The answer is: The cook got (at least) 4003 cows! Some of you recognized the Chinese Remainder Theorem at work. Most solutions consisted of checking one number after another for the right conditions. A bit of preparation makes that task much less daunting. The following explanation is an amalgam of various solutions received. Let n denote the number of cows in the herd. Then n leaves a remainder of 3 upon division by 25, a remainder of 7 upon division by 18, and a remainder of 10 upon division by 11. A common notation
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This note was uploaded on 03/01/2010 for the course MATH 301 taught by Professor Albertodelgado during the Spring '10 term at Bradley.

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s03 - Solution to Problem 3 Congratulations to this week's...

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