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Unformatted text preview: The amount of wire is easily seen to be (d-k) + (D 2 + 4x 2 ) 1/2 . Our task is to minimize this quantity over the interval [0,d] . Straightforward differentiation gives a unique local minimum at the point P = (D 2 /12) 1/2 . This local minimum is a global minimum as long as it is a point in the interval in question, i.e. as long as P < d . In the other case the "V"-shaped configuration yields a minimum....
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This note was uploaded on 03/01/2010 for the course MATH 301 taught by Professor Albertodelgado during the Spring '10 term at Bradley.
- Spring '10