# s08 - 2(2R r(1-r 2(4R 2(1/2 Find the equation of the line...

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Solution to Problem 8 Congratulations to this week’s winner Daniel Reeves There were 6 solutions received. Correct solutions were also received from Kevin Bourrillion, Jeff Decker, Mike Fitzpatrick, Michael Lepley. The equation of the semicircle is y 2 = R 2 - (x-R) 2 . The equation of the other circle is y 2 = r 2 - x 2 . Solve these simultaneously to get their point of intersection having coordinates (r

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Unformatted text preview: 2 /(2R), r(1-r 2 /(4R 2 )) (1/2) . Find the equation of the line going through that point and (0,r). The point of intersection of that line and the x-axis is -r 2 /(R(-2+(4-r 2 /R 2 )) (1/2) ). Take the limit as r goes to 0; it’s of the form 0/0 so use L’Hopital’s Rule once to get 2R(4-r 2 /R 2 ) (1/2) which goes to 4R as r goes 0....
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s08 - 2(2R r(1-r 2(4R 2(1/2 Find the equation of the line...

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