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Unformatted text preview: circle. Then angle EDA is a right angle, angle BAC is 60 degrees and, since EA bisects BAC, BAE is 30 degrees. We are trying to find the length of DA, call it R. The hypotenuse of the triangle EDA is EA and has length r + R. The two sides DA and EA of the 306090 triangle EDA will be in the ratio 3 (1/2) /2, that is, R/(r + R) = 3 (1/2) /2. Therefore R = r / (2/3 (1/2) 1)....
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 Spring '10
 AlbertoDelgado
 Geometry, Combinatorics, Right triangle, Hypotenuse, Right angle, triangle EDA, big circles

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