s15 - 8V = 2S since summing the vertex numbers for each of...

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Solution to Problem 15 Congratulations to this week’s winner Ray Kremer A correct solution was also received from Mike Fitzpatrick. There is a unique smallest solution up to permutations of the cube. See the figure below. The vertex number, V , is 21 and the face number, F , is 28. The integers used are 1 to 6 and 8 to 13. Here’s one way to arrive at the solution. Let S denote the sum of all the edge numbers. Then
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Unformatted text preview: 8V = 2S , since summing the vertex numbers for each of the eight corners sums each of the edges twice. Similarly, 6F = 2S . The equations 4V = S = 3F give that S must be divisible by 12. Since S is at least 1 + 2 + . .. + 12 = 78 , the smallest possible value for S is 84, which is the sum of the integers given above. The rest involves a small amount of trial and error. Labeled Cube...
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This note was uploaded on 03/01/2010 for the course MATH 301 taught by Professor Albertodelgado during the Spring '10 term at Bradley.

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s15 - 8V = 2S since summing the vertex numbers for each of...

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