s46 - A , swept out by a wiper of length L is given by the...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Solution to Problem 46 Congratulations to this week’s winners Nathan Pauli, Ray Kremer A correct solution was also received from Bradley alum Brain Laughlin (’81), Philippe Fondanaiche, Robert T. McQuaid, William Webb. There are numerous variations on the main equation to the problem. If we assume (as we may) that the radius of the porthole is 1 unit, then the area,
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 2
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: A , swept out by a wiper of length L is given by the equation A = L 2 arccos( L/2 ). Solving for A to be half the area of the porthole gives two solutions: L = 2 1/2 , 3 1/2 . A little straightforward calculus gives you a maximum of about 52.45% of the area of the porthole with a wiper of length approximately L = 1.588 ....
View Full Document

Page1 / 2

s46 - A , swept out by a wiper of length L is given by the...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online