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Unformatted text preview: If we write the equation of the parabola in the form f ( x ) = a ( x- b ) 2 + c , then weve already found b = 625. We can differentiate to find that f (x) = 2 a ( x- 625). We know that f (0) = -.05, so we can solve for a and find that a = .00004. Now we just have to plug in our one known point (0, 1250) to solve for c . (a) That gives the equation f ( x ) = .00004( x- 625) 2 + 1234.375 (b) f (1000) = the elevation where the parabola meets the 3% grade = 1240 ft. (c) The drain should be at the lowest point on the parabola, which has location (625, 1234). "...
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This note was uploaded on 03/01/2010 for the course MATH 301 taught by Professor Albertodelgado during the Spring '10 term at Bradley.
- Spring '10