s64 - Solution to Problem 64 Congratulations to this week's...

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Solution to Problem 64 Congratulations to this week’s winners Nathan Pauli, Anna McCullough, Tracy Thatcher Further correct solutions were also received from Silvain Vinassac, Al Zimmermann, Burkart Venzke, Philippe Fondanaiche, William Webb. The easiest solution was presented by Nathan Pauli. It has the advantage of showing that the fact that the triangle is a right triangle is irrelevant since that fact is never used in the solution! [IMAGE] Consider the diagram on the right. The fence, f , is in blue; the units for the lengths of the sides are in hundreds of feet. The area of the entire field is 6 square units, so the fence is to subdivide the field into parts of 3 square units each. Look at the point C which is b units from the corner labeled A . The fence goes to a point labeled B which is c units from A . The angle CAB is labeled q; this gives tan(q) = 3/4, sin(q) = 3/5, and cos(q) = 4/5. Now, the area of triangle
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This note was uploaded on 03/01/2010 for the course MATH 301 taught by Professor Albertodelgado during the Spring '10 term at Bradley.

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s64 - Solution to Problem 64 Congratulations to this week's...

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