HW5_solutions

HW5_solutions - Tinoco 6.5 a) Use excel to plot Time vs....

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Unformatted text preview: Tinoco 6.5 a) Use excel to plot Time vs. log (x), find the slope of the line The slope is 0.0003 min 1 or 5.0 x 10 6 s 1 . We use equation (6.49) from Tinoco for sedimentation coefficient s = 2.303 2 d log( x 1/ 2 ) dt = 1 2 d dt ln( x ) We are given the speed rotation 24,630 revolutions/min. (Recall that the unit radian rad is defined as an arc length divided by a radius and is therefore dimensionless) = 24,630 rev min 2 rad rev 1min 60 s = 2.579 10 3 rad s 2 = 2.579 10 3 rad s 2 = 6.65 10 6 s 2 We can now plug our values for angular velocity and slope into the equation for sedimentation coefficient. s = 1 6.65 10 6 s 2 5.0 10 6 s 1 ( ) = 8.42 10 13 s = 8.42 S [NOTE : depending on whether you chose to use log or ln, the final answer could vary (anywhere from 819S). The important part is being on the right order of magnitude (1.0x10 12 s or about 10S).] y = 0.0003x + 0.7918 0.795 0.8 0.805 0.81 0.815 0.82 0.825 0.83 20 40 60 80 100 120 log(x) Time (min) Time (min) Distance, x (cm) log (x) 16 6.2687 0.797177486 32 6.3507 0.802821598 48 6.438 0.808750972 64 6.5174 0.814074376 80 6.6047 0.819853096 96 6.6814 0.824867473 Tinoco 6.10) (a) Similar to 6.5, plot time vs. ln(x) d dt ln( x ) = 3.00 10 4 min 1 = 5.0 10 6 s 1 s = 1 2 d dt ln( x ) and M = RTs D (1 2 ) _ y = 0.0003x + 1.4959 R = 0.99938 1.49 1.5 1.51 1.52 1.53 1.54 1.55 1.56 1.57 1.58 1.59 80 160 240 320 ln(x) Time (min) Time (min) Boundary position (cm) ln (x) 0 4.46 1.495148766 80 4.593 1.524533405 160 4.713 1.550324648 240 4.844 1.577740826 Additional problem 1)...
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HW5_solutions - Tinoco 6.5 a) Use excel to plot Time vs....

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