CHEM14C_s09_lec01_e02_key

CHEM14C_s09_lec01_e02_key - Chemistry 14C Spring 2009...

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Chemistry 14C Spring 2009 Lecture 1 Exam 2 Solutions Revised 05/19/09 Page 1 Statistics : High score, average, and low score will be posted on the course web site after exam grading is complete. The exam is ready to be picked up when these numbers are posted. Some questions have more than one answer, even though only one answer may be listed here. To see the projected course grade cutoffs, consult the grading scale on the Chemistry 14C course web page. 1. (a) 339 (b) 18.7, 18.8, or 18.9 (depending upon how you round) (c) 5 2. A fragment. In a mass spectrum all peaks with m/z < M are fragments. We cannot determine from this information alone which ion is most abundant, so we cannot decide if m/z = 180 is or is not also the base peak . 3. Among all of the hydrogens in Tripeptide, 8 are not equivalent to any other hydrogen atoms in the molecule. 4. When the smallest integral = 1, the 1 H-NMR spectrum of Tripeptide includes 8 signals of integral = 1, 5 signals of integral = 2, and 1 signal whose integral is more than 2. 5. The 1 H-NMR spectrum of Tripeptide has 6 signals whose chemical shift is greater than 5.0 ppm. 6. Considering only the signals due to hydrogens directly bonded to carbons, the 1 H-NMR spectrum of Tripeptide includes 0 singlets, 2 doublets, and 7 signals more complex than doublets. 7.
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This note was uploaded on 03/02/2010 for the course CHEM CHEM14C taught by Professor Hardinger during the Winter '10 term at UCLA.

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CHEM14C_s09_lec01_e02_key - Chemistry 14C Spring 2009...

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