Exam_2_2009 - N a m e D is c u s s io n s e c tio n P erm M...

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Name ________________________ Discussion section: ___________________ Perm # ____________________________ MCD Biology 110 Second Exam March 4, 2009 PLEASE PRINT YOUR NAME AND PERM # LEGIBLY ON EVERY PAGE OF THIS PACKET. BE SURE THIS PACKET CONTAINS ALL 11 PAGES. CALCULATORS ARE NOT NEEDED OR ALLOWED. READ THESE INSTRUCTIONS: For questions number 1-30 enter your answers on the Scantron form by filling in the appropriate bubble(s) with a #2 pencil. For the remaining questions, write your answer to each question clearly on this exam packet. For the problems involving calculations, your work must be shown in the space provided to receive any credit. Maximum Points Score Pages 4-8 60 _______ (Scantron) Page 8 7 _______ (Non-Scantron) Page 9 7 _______ Page 10 16 _______ Page 11 10 _______ Total 100 _______
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Name ____________________ -2-
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Name ____________________ -3- SOME OF THE FOLLOWING INFORMATION MAY BE USEFUL: log 10 -4 = -4 log 10 = 1 log 10 -3 = -3 log 100 = 2 log 10 -2 = -2 log 1000 = 3 log 10 -1 = -1 log 10,000 = 4 log 1 = 0 Faraday's constant: 100 kJ / mol V. Planck's constant = 7 x 10 -34 J s Vi = Vmax [S] Km + [S] 2.3 x Gas constant x Temperature = 6 kJ / mol pH = pKa + log [A ] [HA] E= h ν a = π r 2 Δ E = Δ E o + 2.3RT nF log [e acceptor] [e donor] Δ G = Δ H - T Δ S Δ G' = Δ G o ' + 2.3RT log [C] c [D] d [A] a [B] b Δ G o ' = 2.3RT log K'eq Δ G o ' = -nF Δ Eo'
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Name ____________________ -4- (20 points). True or False. Indicate the appropriate answer. Enter A = True; B = False on the Scantron form . 1. Common sugars, such as glucose, undergo spontaneous cyclization in water, thereby preventing interconversion between linear and ring forms. 2. Chemical reactions are thermodynamically favored by a lower energy state and increased entropy of the products. 3. The only way a reaction with an unfavorable G ° ’ can be driven to proceed in a cell is by coupling with an energy source such as ATP.
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