Stat 215 Quiz 9

Stat 215 Quiz 9 - Your Answer n = 49 X = 82 Mean = 80 s=7 Z...

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Stat 215 Quiz 9 Module: Quiz , Exercise: HypTest_mu Question A professor is targeting a score of 80 on an exam. His forty-nine students averaged 82 on an exam with s = 7. Are the scores significantly more than 80 at a significance level of 0.05? Show your work and state the conclusion. Answer Z = (82 - 80)/(7/sqrt(49)) = 2 Reject Ho if Z > 1.645 Reject Ho and conclude that the mean score is significantly greater than 80.
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Unformatted text preview: Your Answer n = 49 X = 82 Mean = 80 s=7 Z = (X-mean)/(s/n^0.5) = (82-80)/(7/ (49^0.5) = 2 Z 0.05 = 1.645 Rejection region is R = (-inf, 1.645) The Z observed value from this data was 2, which is not in the rejection region (-inf,1.645) so the data is significantly more than 80. The data is accepted for the 0.05 sig level. Grader Comments (none) Grade 10.0 (out of 10.0) Total 10.0 (out of 10.0)...
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This note was uploaded on 04/03/2008 for the course STAT 215 taught by Professor Dr. during the Spring '08 term at WVU.

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