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0244Pb17an - 2010.cwk (WP)

0244Pb17an - 2010.cwk (WP) - bonding porbital In the...

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Answers to problem 17 - Chemistry 0244 - 2010 Both systems are cyclic, planar (or very close) and fully conjugated. The dication has only two pi electrons and they go, of course, into the lowest bonding MO. The other MOs are empty. If the three-electron system were square, one electron would have to be in a non-
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Unformatted text preview: bonding porbital. In the rectangular system the third electron is in a bonding MO. So, it stretches the sigma bonds just a bit and becomes a rectangle. See Group Problems 16 and 17. CH CH CH CH non bonding...
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