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Unformatted text preview: 1 2 OH OH H 2 O H 2 O axial ring equatorial ring Now how to get from 2 to 1 ? Most organic reactions are reversible, so one way is to protonate the OH, lose water ( the reverse of the last two steps of the forward mechanism written above, but done from 2 not 1- important point!). Now we are at the carbocation and we simply go forward as above to 1. OH H OH 2 H H O H H H H H now go on as in the first part of the problem Alternatively, we could go all the way back to starting material by deprotonating the carbocation and starting all over again as in the original problem. You ll see both these reactions in Chapter 7. H 2 O H 3 O + H H H now go on as in the first part of the problem H H...
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