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Unformatted text preview: 3 ) 3 CCH 2 CH 2 I will be more reactive than (CH 3 ) 3 CCH 2 I. (d) Primary allylic bromides will be more reactive than simple primary bromides, as the transition state for displacement will be stabilized. So, the compound with the double bond will be more reactive in the S N 2 displacement than will the simple primary bromide. (e) The strained three-membered ring will be opened much more easily than the relatively unstrained five-membered ring (which actually will be very unreactive in the S N 2 reaction) But see the detailed answer to the next Problem....
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- Fall '10