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20090306153509 - MATSE 290 Spring semester 1997 Quiz No.1...

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Unformatted text preview: MATSE 290 Spring semester 1997 . Quiz No.1 Name .................................... .. Q1 The uniform bar B weighs 1000 N and is in equilibrium in the horizontal position as shown on the right. (a) Draw the free-body diagrams (FBD) for the bar B and for the pulley at the roof showing all forces on them and write down the equilibrium equations for each. (15 pts) (b) Find the tension in the cable, the reactions exerted by the pin at A onto the bar and the force needed at the roof to hold the pulley there. (15 pts) (c) If the location of the pulley at the roof was changed until it was directly above the center of the beam how will the forces change? (15 pts) (d) Describe (without calculations) how you think the forces will Change as the pulley is gradually moved until it is directly above the right hand end of the beam. (5 pts) Q“: iOOCN PM W (2,ch a} 1110} «um.» 3a*r81>+53*i0003 = GD FWWV 'Wuv’b @Wiilzutw 314’ m A . +J<Rgsm9 — «000g: 0, @ a, Rpm: +Tcm 9 CL ® 2'3? 9CCDWkgM—E ‘ .TCOQE’ '1'- O : T+ TSMG TéCCMHW‘M 9&3 + T+Tsme~ i006 ‘0 M..,«..&, + waging 2 500 3‘ -Rnoc 4 dogmade 33 '1- : 5300 wok R. +QP : Winn __ ‘Lt—S‘me 9'3 U 3.0? g : 45“: Saw: $3 4 ‘T‘ 2 am It Ra x: 329 N . ‘3‘" my“: r 8351 p gr“; ‘7': .T-CLOO E’ : ( Coo g ‘ Q03 x: ‘08 Ni oi: 45‘ l “1'3 = lQOO‘TU+S”"9) JJ'FSI’AB .. ‘ = toee — $00 t~+sme Q : «seas; that?) £2ng Skis; N iRpl "- (ich V. ‘50 l4 a q I, :1 c t ‘ a z .t . _ mg 9% ¢=QQ6 lt§f§%afr*% (WP) ‘4 14+ Tan/cf) V 4 . (c009~C—DO4>) am ~= Wmvwe) = «we : 9,- Q.-r~ =‘ ' N 4‘07 (J (\37’3 0‘70) Hi 5 W I Raj 3' ‘O‘QO ‘TLSKV 9+$Mfif>> ‘&%— ‘ =157~3N Qfim‘m OWCQQQEM/ CtLS vs 39C!) “no Kw»qu ((9753 K38) «- m MATSE 290 Spring semester 1997. Quiz No.1 Name .................................... .. Q2. The uniform door weighing lZOON is held in equilibrium in the horizontal position by the cable and by the smooth hinges at A and B as a shown on the right. (a) Draw the free-body - diagrams for the door indicating clearly what force and moment reactions are needed at hinges A and B. (15 pts) (b) Without solving them, write the equations for equilibrium of the door. (10 pts) (c) If T represents the tension in the cable, express T as a vector in cartesian coordinates and use this to calculate the moment about the line of _, , the hinges i.e. the line AB, of the weight of the 1.5 door and the tension force in the cable. (10 pts) 7 ' (d) Use this moment to determine the tension in 0:5,"1 / , the Cable (15 ms) (6) Describe (without / lm—*—~*/ ; I calculations) why you think the forces cannot be Lei: C be was «aim w calculated. (5 pts) Qiétcfikbwo (111 A ouuz. BA L’UAQAXI,’ RAE; IRA: ) 8 a . Um w or; WWW db A; ‘3 MA : (“4435+ Mfg mg lip/‘85 "Melisa 13: - i a __ _ 2W“? a :19 ea. + m»st -+- new: :0 a \O wamom 4. T (_ H Mat (a gamma/3 Wm, . A _ ._ . N I =l1‘l (IE-<23) = W.) ‘ W3” Visa“? (Bee: mwggms i... O {x , IR A ‘ a . ‘7 . A "* O : gvmf/izegxfisl 4” @eevimwwal + gfig‘l’i‘wflf) b (i H FT ‘37 9 to] \ U/ / A r\ A . l” = on"? «F? T' -x A\ .~I\ gag 5w)“ H K M3 EW—E. w: 0 f8 View) = RT x 3 NM \hS-S .‘f. T: {QOOXQI‘szS‘M =787N (‘9 Q1) Too Maud vW; -- egpmfibc‘m_ ...
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