fall 2005 STAT 230 Test2

# fall 2005 STAT 230 Test2 - 1(a PX 0|A 75 3 421 88 by...

This preview shows pages 1–2. Sign up to view the full content.

1(a) P X 0| A .75 3 . 42188,by independence (b)We want to calculate P A | X 0 . Note that: P A | X 0 P X 0| A P A P X 0 , by Bayes rule P X 0| A was calculated in part (a). P A 0.4, given information To calculate P X 0 use the partion rule P X 0 P X 0| A P A P X 0| B P B P X 0| C P C .75 3 0.4 .8 3 0.2 .85 3 0.4 (c) X can take on the values: 0,1,2,3 To find f x let us use the partition rule once again, f x P X x P X x | A P A P X x | B P B P X x | C P C 3 x .25 x .75 3 x 0.4 3 x .2 x .8 3 x 0.2 3 x .15 x .85 3 x 0.4 for x 0,1,2,3. (d)

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 2

fall 2005 STAT 230 Test2 - 1(a PX 0|A 75 3 421 88 by...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online